A. lim(x→2) x-2/x²-4x+4
B. lim(x→∞）x+1/2x-1
C. lim(x→∞）1-x/3+2x
D. lim(x→∞）x²+1/2x³+5
可以幫我解一下四題極限四則運算的題目嗎（附過程）?
2017-10-19 10:53 pm
回答 (2)
2017-10-20 6:28 am
✔ 最佳答案
ALim(x→2)_(x－2)/(x^2－4x+4) = lim(x→2)_1/(x－2)
不存在
B. lim(x→∞)_(x+1)/(2x－1)
= lim(x→∞)_(1+1/x)/(2－1/x)
=1/2
C. lim(x→∞)_(1－x)/(3+2x)
= lim(x→∞)_(1/x－1)/(3/x+2)
=-1/2
D. lim(x→∞)_(x^2+1)/(2x^3+5)
=lim(x→∞)(1/x+1/x^3)/(2+5/x^3)
=(0+0)/(2+9)
=1/2
2017-10-20 9:05 pm
=lim(x→∞)(1/x+1/x^3)/(2+5/x^3)
=(0+0)/(2+9) ???????????=1/2
'
=(0+0)/(2+9) ???????????=1/2
'
收錄日期: 2021-04-24 00:46:51
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20171019145330AARtc0T