請問這題怎麼解?(附過程)謝謝?

2017-10-19 10:29 pm

回答 (1)

2017-10-20 6:54 am
✔ 最佳答案
lim(x→2)_(x-2)/(x^2-4x+4)
= lim(x→2)_1/(x-2)
(1)
lim(x→2+)_(x-2)/(x^2-4x+4)
= lim(x→2+)_1/(x-2)
=∞
(2)
lim(x→2-)_(x-2)/(x^2-4x+4)
= lim(x→2-+)_1/(x-2)
=-∞
不存在


收錄日期: 2021-04-30 22:26:26
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20171019142912AAmQhCl

檢視 Wayback Machine 備份