Calculate the heat change in calories for condensation of 18.0 g of steam at 100∘C.?

[匿名]

2017-10-18 10:56 am

回答 (1)

胡雪8°

2017-10-18 11:11 am

✔ 最佳答案

Specific latent heat of vaporization of water at 100°C = 2260 J/g

Heat change = (18.0 g) × (2260 J/g) = 40700 J = 40.7 kJ

參考: https://en.wikipedia.org/wiki/Latent_heat

👍 3 👎 2

收錄日期: 2021-05-01 13:12:13
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20171018025653AA1aAo1

檢視 Wayback Machine 備份