what is the enthalpy per mole of aluminum oxide if the reaction of 5.32g of aluminum oxide release 38.93 KJ of heat?
回答 (1)
2017-10-16 6:40 pm
Molar mass of Al₂O₃ = (27.0×2 + 16.0×3) g/mol = 102.0 g/mol
No. of moles of Al₂O₃ = (5.32 g) / (102.0 g/mol Al₂O₃) = 0.0522 mol
Enthalpy per mole of Al₂O₃ = (38.93 kJ) / (0.0522 mol Al₂O₃) = 746 kJ/mol Al₂O₃
No. of moles of Al₂O₃ = (5.32 g) / (102.0 g/mol Al₂O₃) = 0.0522 mol
Enthalpy per mole of Al₂O₃ = (38.93 kJ) / (0.0522 mol Al₂O₃) = 746 kJ/mol Al₂O₃
收錄日期: 2021-04-18 17:55:09
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