When heated KlCO₃ decomposes into KCl and O₂. 2KClO₃-->2KCl+3O₂ If this reaction produced 81.5 grams of KCl, how much O₂ was produced?

Molar mass of KCl = (39.0 + 35.5) g/mol = 74.5 g/mol
Molar mass of O₂ = 16.0 × 2 g/mol = 32.0 g/mol

2KClO₃ → 2KCl + 3O₂
Mole ratio KCl : O₂ = 2 : 3

No. of moles of KCl produced = (81.5 g) / (74.5 g/mol) = 1.09 mol
No. of moles of O₂ produced = 1.09 mol × (3/2) = 1.64 mol
Mass of O₂ produced = (1.64 mol) × (32.0 g/mol) = 52.5 g