Reacting 3.00 mol N2 with 7.95 mol H2 will produce how many moles of ammonia according to the following balanced chemical equation?
回答 (1)
2017-10-16 7:27 pm
The balanced equation for the reaction :
N₂(g) + 3H₂(g) → 2NH₃(g)
Mole ratio N₂ : H₂ : NH₃ = 1 : 3 : 2
When 7.95 mol H₂ completely reacts, N₂ needed = (7.95 mol) × (1/3) = 2.65 mol < 3.00 mol
Hence, N₂ is in excess, and 7.95 mol H₂ completely reacts.
No. of moles of NH₃ produced = (7.95 mol) × (2/3) = 5.30 mol
N₂(g) + 3H₂(g) → 2NH₃(g)
Mole ratio N₂ : H₂ : NH₃ = 1 : 3 : 2
When 7.95 mol H₂ completely reacts, N₂ needed = (7.95 mol) × (1/3) = 2.65 mol < 3.00 mol
Hence, N₂ is in excess, and 7.95 mol H₂ completely reacts.
No. of moles of NH₃ produced = (7.95 mol) × (2/3) = 5.30 mol
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