微積分 數學 e 常數 (e constant ) , 2.7xxx ??? 是從那裏 來的 ? 公式 :: e^(i*theata) = cos(theata)+ i*(sin(theata)); 為何正確 ???? 如何證明 ?

2017-10-14 7:30 am
更新1:

=(1-x^2/2!+x^4/4!-x^6/6!+…)+i(x-x^3/3!+x^5/5!-x^7/7!+…) -Sinx+iCosx //...................................................................................................................... Error : ans: cos(theata)+i*sin(theata) please, corret it . can give you, Best ans !!

回答 (1)

2017-10-14 5:14 pm
✔ 最佳答案
Sol
e^x=1+x+x^2/2!+x^3/3!+x^4/4!+…
e^1=1+1+1/2!+1/3!+1/4!+...2.7*****
Sinx=x-x^3/3!+x^5/5!-x^7/7!+…
Cosx=1-x^2/2!+x^4/4!-x^6/6!+…
e^(ix)=1+ix+(ix)^2/2!+(ix)^3/3!+(ix)^4/4!+(ix)^5/5!+(ix)^6/6!+(ix)^7/7!+…
=1+ix-x^2/2!-ix^3/3!+x^4/4!+ix^5/5!-x^6/6!-ix^7/7!+…
=(1-x^2/2!+x^4/4!-x^6/6!+…)+i(x-x^3/3!+x^5/5!-x^7/7!+…)
-Sinx+iCosx


收錄日期: 2021-04-30 22:33:44
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20171013233000AAVl8iH

檢視 Wayback Machine 備份