How many grams of Cu(OH)2 will precipitate when excess NaOH solution is added to 64.0 mL of 0.596 M CuBr2 solution?

👨🏻‍🏫 學術台化學

[匿名]

2017-10-14 5:44 am

回答 (1)

Roger the Mole

2017-10-14 9:42 am

2 NaOH + CuBr2 → Cu(OH)2 + 2 NaBr

(0.0640 L) x (0.596 mol/L CuBr2) x (1 mol Cu(OH)2 / 1 mol CuBr2) x (97.5607 g Cu(OH)2/mol) =
3.72 g Cu(OH)2

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