A 4.91-mol sample of aluminum represents how many atoms?
回答 (1)
2017-10-09 2:54 pm
Avogadro constant = 6.022 × 10²³/mol
No. of Al atoms = (4.91 mol) × (6.022 × 10²³/mol) = 2.96 × 10²⁴
No. of Al atoms = (4.91 mol) × (6.022 × 10²³/mol) = 2.96 × 10²⁴
收錄日期: 2021-04-18 17:52:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20171009064531AAtVcXM