please help with chemistry problem?

[匿名]

2017-10-02 11:19 am

You drop a silver cube into the 304 g aluminum cup of a well-insulated calorimeter containing 95.0 g of liquid water and 125 g of ice, all at 0.0°C. The bear’s initial temperature is 97.0°C. The final temperature of the cup and its contents is 15.0°C. The specific heat of silver is 0.234 J/g·°C and the specific heat of aluminum is 0.910 J/g·°C. Selected constants for water are provided on your equation sheet. Using this information, calculate the mass of the silver cube

回答 (1)

不用客氣

2017-10-02 4:10 pm

✔ 最佳答案

Latent heat of fusion of ice = 334 J/g
Specific heat of water = 4.184 J/g°C

Let m g be the mass of the silver cube.

Heat released by the silver cube = (m g) × (0.234 J/g°C) × (97.0 - 15.0)°C = 19.188m J
Heat absorbed by the aluminum cup = (304 g) × (0.910 J/g°C) × (15.0 - 0.0)°C = 4149.6 J
Heat absorbed on the melting of ice = (125 g) × (334 J/g) = 41750 J
Heat absorbed by the liquid water = [(95.0 + 125) g] × (4.184 J/g°C) × (15.0 - 0.0)°C = 13807.2 J

Total heat released in J = Total heat absorbed in J
19.188m = 4149.6 + 41750 + 13807.2
m = 3110
Mass the silver cube = 3110 g

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