更新1:
Edit: turns out I read the question wrong so ignore this
What two numbers have a product of negative 10 and a sum of 1?
回答 (2)
2017-09-28 7:26 am
xy=-10
x+y = 1
x-10/x = 1
x^2-x-10 = 0
x = [1±√41]2
Numbers are [1-√41]/2 and [1+√41]/2
x+y = 1
x-10/x = 1
x^2-x-10 = 0
x = [1±√41]2
Numbers are [1-√41]/2 and [1+√41]/2
2017-09-28 7:25 am
There are no rational numbers that satisfy the conditions.
The numbers are (1 + √41)/2 and (1 - √41)/2 or approximately 3.702 and -2.702
Perhaps you imagine it makes no sense because trinomials don't always have rational factors.
The numbers are (1 + √41)/2 and (1 - √41)/2 or approximately 3.702 and -2.702
Perhaps you imagine it makes no sense because trinomials don't always have rational factors.
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170927231858AAmWylI