Perform the operation and write the result in standard form. (i/3-2i)+(3+2i)/(3+8i). See picture also. ?

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Gurgle!

Do you mean i/(3-2i) ?

　
The picture doesn't show (i/3-2i)+(3+2i)/(3+8i)
It shows: i/(3-2i) + 2i/(3+8i)


i/(3−2i) + 2i/(3+8i)
= i(3+2i) / ((3−2i)(3+2i)) + 2i(3−8i) / ((3+8i)(3−8i))
= (3i+2i²) / (9+4) + (6i−16i²) / (9+64)
= (−2+3i)/13 + (16+6i)/73
= (73(−2+3i) + 13(16+6i)) / (13*73)
= ((−146+219i) + (208+78i)) / 949
= (62 + 297i) / 949
= 62/949 + 297/949 i