Precalc: evaluate e^(ln (√11))? and log5(5^8)?

👨🏻‍🏫 學術台數學

[匿名]

2017-09-27 1:04 am

回答 (4)

用戶48544

2017-09-27 1:16 am

✔ 最佳答案

　
e^(ln x) = x ------> e^(ln(√11)) = √11
logₐ(a^x) = x ----> log₅(5^8) = 8

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胡雪8°

2017-09-27 1:19 am

Please read :

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[匿名]

2017-09-27 1:19 am

e^[ln (√11)] = √11 (Rule: a^(log_a (x)) = x).

log_5(5^8) = 8 (Rule: log_a (a^x) = x).

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[匿名]

2017-09-27 1:10 am

** e^ln ( V11) = V(11) because lne = e^ln = 1
** log5 (5^8) = 8 because log base 5 of a number 5 = 1

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