How many g of ethanol should made from 60 g of glucose?

Molar mass of C₆H₁₂O₆ (glucose) = (12.0×6 + 1.0×12 + 16.0×6) g/mol = 180.0 g/mol
Molar mass of C₂H₅OH (ethanol) = (12.0×2 + 1.0×6 + 16.0) g/mol = 46.0 g/mol

The equation for the reaction of making ethanol from glucose :
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
Mole ratio C₆H₁₂O₆ : C₂H₅OH = 1 : 2

No. of moles of C₆H₁₂O₆ reacted = (60 g) / (180 g/mol) = 1/3 mol
No. of moles of C₂H₅OH made = (1/3 mol) × 2 = 2/3 mol
Mass of C₂H₅OH made = (2/3 mol) × (46.0 g/mol) = 30.7 g

Balanced equation:
C6H12O6 → 2 C2H5OH + 2 CO2
1mol glucose produces 2 mol ethanol
Molar mass C6H12O6 = 180g/mol
Mol C6H12O6 in 60g = 60/180 = 0.333 mol
This will produce 0.333*2 = 0.666 mol ethanol
Molar mass C2H5OH 46g/mol
Mass of 0.666 mol = 0.666*46 = 30.6g ethanol produced.

No