How do I solve them? Please someone teach me! 6x^8+9x^7+33x^5 3√13x+16√13x (7x^2 y^6 z^9)(5x^10y^7)?
回答 (5)
2017-09-26 1:45 pm
✔ 最佳答案
6x^8 + 9x^7 + 33x^5 = 3^5 (2x^3 + 3x^2 + 11)
3√13x+16√13x
= 19√13x
(7x^2 y^6 z^9)(5x^10 y^7)
= (7*5)x^(2 + 10) y^(6 + 7) z^9
= 35x^12 y^13 z^9
2017-09-26 1:43 pm
These are expressions, and cannot be solved (no equal sign).
It can be rearranged, reordered, factored, etc., but cannot be solved.
6x^8+9x^7+33x^5
3x⁵ is in common so factor it out
3x⁵(2x³ + 3x² + 11)
It can be rearranged, reordered, factored, etc., but cannot be solved.
6x^8+9x^7+33x^5
3x⁵ is in common so factor it out
3x⁵(2x³ + 3x² + 11)
2017-09-26 1:49 pm
You've listed a bunch of numbers. What do you need to learn how to do with them?
2017-09-26 1:47 pm
Get math photo App Store
2017-09-26 1:46 pm
1).
6x^8 + 9x^7 + 33x^5
= 3x^5(2x^3 + 3x^2 + 11)
Real roots:
x = 0
x ≈ -2.4308
Complex roots:
x ≈ 0.4654 - 1.4304 I
x ≈ 0.4654 + 1.4304 i
2).
3√13x + 16√13x
= 19√13x
3).
(7x^2 y^6 z^9)(5x^10y^7)
= 35x^12y^13z^9
6x^8 + 9x^7 + 33x^5
= 3x^5(2x^3 + 3x^2 + 11)
Real roots:
x = 0
x ≈ -2.4308
Complex roots:
x ≈ 0.4654 - 1.4304 I
x ≈ 0.4654 + 1.4304 i
2).
3√13x + 16√13x
= 19√13x
3).
(7x^2 y^6 z^9)(5x^10y^7)
= 35x^12y^13z^9
收錄日期: 2021-04-18 17:51:57
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170926053443AAQv4Aq