In how many ways can a committee of 6 be chosen from 8 men and 9 women if the committee
must not have more men than women?
Permutation and Combination?
2017-09-25 5:17 pm
回答 (1)
2017-09-26 10:22 pm
✔ 最佳答案
Case 1: 6 women and 0 men9P6 x 8P0 = 60480
Case 2: 5 women and 1 men
9P5 x 8P1 = 120960
Case 3: 4 women and 2 men
9P4 x 8P2 = 169344
Case 4: 3 women and 3 men
9P3 x 8P3 = 169344
Therefore, there are 60480 + 120960 + 169344 = 520128 ways
收錄日期: 2021-04-18 17:50:59
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170925091706AAWUA9i