請問以下呢條數點做? Solve 8^(x-2)=3(4^2x)?
回答 (3)
2017-09-25 4:06 pm
8^(x-2)=3(4^2x)
2^[(3)(x-2)]=(3)(2)^4x
2^(3x-6-4x)=3
2^(-6-x)=3
(-6-x)log2=log3
-6-x=log3/log2
2^[(3)(x-2)]=(3)(2)^4x
2^(3x-6-4x)=3
2^(-6-x)=3
(-6-x)log2=log3
-6-x=log3/log2
2017-09-25 3:37 pm
8^(x-2)=3(4^2x)
2^(3x-6)=3(2^4x)
2^x=3(2^6)
x log 2=log 3+6 log 2
x=7.58
2^(3x-6)=3(2^4x)
2^x=3(2^6)
x log 2=log 3+6 log 2
x=7.58
收錄日期: 2021-04-18 17:49:35
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