what is the final ph of solution by mixing 100ml of 0.05m acetate acid and 100ml of 0.1m sodium acetate ?
回答 (1)
2017-09-19 5:59 pm
In the mixture, [CH₃COOH]/[CH₃COO⁻] = 0.05/0.1
CH₃COOH(aq) ⇌ CH₃COO⁻(aq) + H⁺(aq) …… Ka = 1.8 × 10⁻⁵
pH = pKa + log([CH₃COOH]/[CH₃COO⁻]) = -log(1.8 × 10⁻⁵) + log(0.05/0.1) = 4.4
CH₃COOH(aq) ⇌ CH₃COO⁻(aq) + H⁺(aq) …… Ka = 1.8 × 10⁻⁵
pH = pKa + log([CH₃COOH]/[CH₃COO⁻]) = -log(1.8 × 10⁻⁵) + log(0.05/0.1) = 4.4
收錄日期: 2021-04-18 18:04:11
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https://hk.answers.yahoo.com/question/index?qid=20170919094026AAuU8nk