Consider g(x)=2x^(2)+ax where a is a constant and g(-1)=1. If a=1, g(t)=6, find the values of t.?
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2017-09-17 10:05 am
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Consider g(x)=2x^2+ax where a is a constant and g(－1)=1，If a=1，g(t)=6， find the values of t.?Sol
g(－1)=2－a=1
a=1
g(x)=2x^2+x
g(t)=2t^2+t=6
2t^2+t－6=0
(2t－3)(t+2)=0
t=3/2 or t=－2
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