國中數學1131的平方-1132*1135+2266=a*1131,則a=?
回答 (3)
2017-09-14 12:20 pm
國中數學1131^2－1132*1135+2266=a*1131,則a=?
Sol
p=1131
1131^2－1132*1135+2266
=p^2－(p+1)(p+4)+2p+4
=p^2－(p^2+5p+4)+2p+4
=－3p
a=－3
Sol
p=1131
1131^2－1132*1135+2266
=p^2－(p+1)(p+4)+2p+4
=p^2－(p^2+5p+4)+2p+4
=－3p
a=－3
2017-09-14 8:38 pm
a=(1131^2-1132*1135+2266)/1131
a=-3
a=-3
2017-09-13 11:22 pm
1131^2 - 1132 x 1135 + 2266 = a x 1131
(1133 - 2)^2 - (1133 - 1)(1133+2) + 2 x 1133 = a x 1131
1133^2 - 4(1133) + 4 - 1133^2 - 1133 + 2 + 2(1133) = 1131a
-3(1133) + 6 = 1131a
-3(1133 - 2) = 1131a
-3(1131) = 1131a
a = -3
(1133 - 2)^2 - (1133 - 1)(1133+2) + 2 x 1133 = a x 1131
1133^2 - 4(1133) + 4 - 1133^2 - 1133 + 2 + 2(1133) = 1131a
-3(1133) + 6 = 1131a
-3(1133 - 2) = 1131a
-3(1131) = 1131a
a = -3
收錄日期: 2021-04-24 00:41:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170913134124AAU6bjg