Find the inverse of F(x)=x+1/x-2?
回答 (5)
2017-09-12 4:57 pm
y = F(x) = (x + 1)/(x - 2)
y = (x + 1)/(x - 2)
y(x - 2) = x + 1
xy - 2y = x + 1
xy - x = 2y + 1
x(y - 1) = 2y + 1
x = (2y + 1)/(y - 1)
F⁻¹(x) = (2x + 1)/(x - 1)
y = (x + 1)/(x - 2)
y(x - 2) = x + 1
xy - 2y = x + 1
xy - x = 2y + 1
x(y - 1) = 2y + 1
x = (2y + 1)/(y - 1)
F⁻¹(x) = (2x + 1)/(x - 1)
2017-09-12 4:50 pm
I'll invert my foot in your @$$ if you ever speak to me like that again
2017-09-12 4:50 pm
Trump's tax returns..
2017-09-12 9:47 pm
y = (x+1)/(x-2)
Switch x and y
x = (y+1)/(y-2)
solve for y
multiply both sides by y-2
x(y-2) = y+1
xy-2x = y+1
xy-y = 2x+1
y(x-1) = 2x+1
divide both sides by x-1
y = (2x+1)/(x-1)
f^-1(x) = (2x+1)/(x-1)
Switch x and y
x = (y+1)/(y-2)
solve for y
multiply both sides by y-2
x(y-2) = y+1
xy-2x = y+1
xy-y = 2x+1
y(x-1) = 2x+1
divide both sides by x-1
y = (2x+1)/(x-1)
f^-1(x) = (2x+1)/(x-1)
2017-09-12 6:06 pm
Will assume that should be shown with brackets as :-
f (x) = y = (x + 1) / (x - 2)
y = (x + 1) / (x - 2)
y x - 2y = x + 1
( y - 1 ) x = 1 + 2 y
x = ( 1 + 2y ) / ( y - 1 )
g (y) = ( 1 + 2y ) / ( y - 1 )
g (x) = (1 + 2x ) / ( x - 1)
f (x) = y = (x + 1) / (x - 2)
y = (x + 1) / (x - 2)
y x - 2y = x + 1
( y - 1 ) x = 1 + 2 y
x = ( 1 + 2y ) / ( y - 1 )
g (y) = ( 1 + 2y ) / ( y - 1 )
g (x) = (1 + 2x ) / ( x - 1)
收錄日期: 2021-04-18 17:52:44
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