更新1:
After the reaction how much octane is left?
2C8H18+25O2→16CO2+18H2O The question asks how much octane can react with 0.890 mol of oxygen?
回答 (1)
2017-09-12 1:17 pm
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
Mole ratio C₈H₁₈ : O₂ = 2 : 25
No. of moles of O₂ reacted = 0.890 mol
No. of moles of C₈H₁₈ reacted = (0.890 mol) × (2/25) = 0.0712 mol
Mole ratio C₈H₁₈ : O₂ = 2 : 25
No. of moles of O₂ reacted = 0.890 mol
No. of moles of C₈H₁₈ reacted = (0.890 mol) × (2/25) = 0.0712 mol
收錄日期: 2021-05-01 13:43:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170912035858AAJiPKW