x的平方=151的平方+132的平方+85的平方-19的平方,求x? 急~~!!!拜託!!!要有過程!!! (已知答案應該為217)?

2017-09-10 3:57 pm
更新1:

(2)4的16次方=2的幾次方

回答 (4)

2017-09-10 4:06 pm
✔ 最佳答案
1 x^2=151^2+132^2方+85^2-19^2,求x?
Sol
x^2=(151^2-19^2)+132^2+85^2
=(151+19)*(151-19)+132^2+85^2
=170*132+132^2+85^2
=132^2+2*132+85+84^2
=(132+85)^2
=217^2
x=+/-217
版本提供解答少一個答案
2
4^16=(2^)^16=2^32
2017-09-10 4:15 pm
Q.1.

x^2 = 151^2 + 132^2 + 85^2 - 19^2

x^2 = (151^2 - 19^2) + 132^2 + 85^2

x^2 = (151+19)(151-19) + 132^2 + 85^2

x^2 = (170)(132) + 132^2 + 85^2

x^2 = 132^2 + (170)(132) + 85^2

x^2 = 132^2 + 2(85)(132) + 85^2

x^2 = (132 + 85)^2

x^2 = (217)^2

x = 217

Q.2.

4^16

= (2^2)^16

= 2^32
2017-09-10 4:17 pm
謝謝!!!!!
2017-09-11 10:47 am
151X151=22801
132X132=17424
85X85=7225
19X19=361
22801+17424+7225-361=47089
47089開根號=217


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