lim(h->0) (47 x^12 + 38 xh^3 + 3 x^14 h + 28) I thought I understood limits but now.... Please help?
回答 (3)
2017-08-30 2:31 pm
✔ 最佳答案
lim (47x¹² + 38x h³ + 3x¹⁴ h + 28)h→0
= 47x¹² + 38x(0)³ + 3x¹⁴(0) + 28
= 47x¹² + 28
2017-08-30 3:54 pm
Can't you even simplify a couple of terms?
2017-08-30 2:34 pm
Just do it by direct substitution:
Lim(h->0) (47 x^12 + 38 xh^3 + 3 x^14 h + 28) = 47x^(12) + 28
Lim(h->0) (47 x^12 + 38 xh^3 + 3 x^14 h + 28) = 47x^(12) + 28
收錄日期: 2021-04-18 17:47:34
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https://hk.answers.yahoo.com/question/index?qid=20170830062722AA1Dx1T