If water is added to 28.43mL of a 12.63M Ca(NO3)2solution to make150mL of solution, then what is the final concentration of calcium nitrate?

[匿名]

2017-08-30 9:21 am

回答 (2)

wanszeto

2017-08-30 11:15 am

✔ 最佳答案

Initial: C₁ = 12.63 M, V₁ = 28.43 mL
Final: C₂ = ? M, V₂ = 150 mL

C₁ × V₁ = C₂ × V₂
Then C₂ = C₁ × (V₁/V₂)

Final concentration, C₂ = (12.63 M) × (28.43 / 150) = 2.394 M

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david

2017-08-30 9:26 am

(28.43 X 12.63) / 150 ... use a calculator

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