If water is added to 28.43mL of a 12.63M Ca(NO3)2solution to make150mL of solution, then what is the final concentration of calcium nitrate?
回答 (2)
2017-08-30 11:15 am
✔ 最佳答案
Initial: C₁ = 12.63 M, V₁ = 28.43 mLFinal: C₂ = ? M, V₂ = 150 mL
C₁ × V₁ = C₂ × V₂
Then C₂ = C₁ × (V₁/V₂)
Final concentration, C₂ = (12.63 M) × (28.43 / 150) = 2.394 M
2017-08-30 9:26 am
(28.43 X 12.63) / 150 ... use a calculator
收錄日期: 2021-04-24 00:40:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170830012102AAWUVmA