Difference quotient math help please?

2017-08-28 4:57 am
更新1:

The problem is Use the limit definition to find the slope of the tangent line to the graph of f at the given point. f(x) = 4; (-5,4) Not having an x in the f(x) is throwing me off in using the difference quotient(???)

回答 (3)

2017-08-28 5:05 am
The difference quotient is:

[f(x + h) - f(x)] / h

And then if you take the limit of h as it approaches zero, you get the first derivative of the original function.

So if you have f(x) = 4, then the output of the function regardless of input is 4, so we end up with:

[4 - 4] / h
0 / h

So as h approaches zero, this expression approaches zero.

So the slope of the line at all points is zero.
2017-08-28 4:59 am
Slope = [4-4]/h = 0
2017-08-28 5:28 am
f(x) = 4 is a constant function, not a number
Its value is 4 no matter what the input to f, so for example f(-5)=4, f(h)=4, f(17)=4, f(-5+h)=4, etc.
So, just use the usual formula for difference quotient.


收錄日期: 2021-04-24 00:38:50
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170827205726AACCOpk

檢視 Wayback Machine 備份