Solve 4x (2x+5) ^3 (2x-1) ^1/3=6x (2x+5)^3 (2x-1) ^2/3?

4 x (2x + 5)^3 (2x - 1)^(1/3) = 6 x (2x + 5)^3 (2x - 1)^(2/3)
4 x (2x + 5)^3 (2x - 1)^(1/3) - 6 x (2x + 5)^3 (2x - 1)^(2/3) = 0
x (2x + 5)^3 (2x - 1)^(1/3) [4 - 6 (2x - 1)^(1/3)] = 0
x = 0 or (2x + 5)^3 = 0 or (2x - 1)^(1/3) = 0 or 6 (2x - 1)^(1/3) = 4
x = 0 or 2x + 5 = 0 or 2x - 1 = 0 or (2x - 1)^(1/3) = 2/3
x = 0 or x = -5/2 or x = 1/2 or 2x - 1 = (2/3)^3
x = 0 or x = -5/2 or x = 1/2 or 2x - 1 = 8/27
x = 0 or x = -5/2 or x = 1/2 or 2x = 35/27
x = 0 or x = -5/2 or x = 1/2 or x = 35/54

4x (2x+5) ^3 (2x-1) ^1/3 = 6x (2x+5)^3 (2x-1) ^2/3

x(2x + 5)^3(2x - 1)^1/3(4 - 6(2x - 1)^1/3 = 0

x = 0

2x - 5 = 0

x = 5/2

= 2.5

2x - 1 = 0

x = 1/2

6(2x - 1)^1/3 = 4

(2x - 1)^1/3 = 4/6

2x - 1 = ( 2/3)^3

2x - 1 = 8/27

2x = 1 + 8/27

= 35/27

x = 35/54

x = 0, 5/2, 1/2, 35/54

4x (2x + 5) ^3 (2x - 1) ^1/3 = 6x (2x + 5)^3 (2x - 1) ^2/3
4x = 6x (2x - 1) ^1/3
2x = 3x (2x - 1) ^1/3

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