A solution has [OH−][OH−]= 1.5×10−2 M . Use the ion product constant of water Kw=[H3O+][OH−] to find the [H3O+] of the solution.?
回答 (2)
2017-08-23 6:18 pm
[OH⁻] = 1.5 × 10⁻² M
[H₃O⁺] = Kw / [OH⁻] = (1.0 × 10⁻¹⁴) / (1.5 × 10⁻²) M = 6.7 × 10⁻¹³
[H₃O⁺] = Kw / [OH⁻] = (1.0 × 10⁻¹⁴) / (1.5 × 10⁻²) M = 6.7 × 10⁻¹³
2017-08-23 4:24 pm
[OH-][ OH-] = [OH-]^2 = 1.5 x 10^-2 => [ OH-] = 1.2 x 10-1
Kw = 1 x 10^-14 = [H3O+][ OH-] => [ H3O+] = 1 x 10^-14 / 1.2 x 10^-1 = 0.82 x 10^-13
Kw = 1 x 10^-14 = [H3O+][ OH-] => [ H3O+] = 1 x 10^-14 / 1.2 x 10^-1 = 0.82 x 10^-13
收錄日期: 2021-04-18 17:45:12
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