For the following endothermic reaction;
2 CH2Cl2 (g)⇌ CH4 (g)+ CCl4 (g)
At equilibrium at a given temperature, the concentrations of CH4 and CCl4 are both 0.2 M and the concentration of CH2Cl2 is 0.021 M.
Write an expression for the equilibrium constant. (2 marks)
Calculate a value for Kc for this reaction under these conditions. Make sure you show the working out. (2 marks)
Does Kc have units or not? Show your workings. (1 mark)
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2017-08-22 11:23 pm
回答 (1)
2017-08-22 11:36 pm
2CH₂Cl₂(g) ⇌ CH₄(g) + CCl₄(g) …… Kc
Equilibrium constant, Kc = [CH₄] [CCl₄] / [CH₂Cl₂]
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At equilibrium:
[CH₄] = [CCl₄] = 0.2 M
[CH₂Cl₂] = 0.021 M
Kc = [CH₄] [CCl₄] / [CH₂Cl₂] = (0.2 M)² / (0.021 M)² = 91
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Kc does not have unit.
Kc = (0.2 M)² / (0.021 M)² = (0.2² M²) / (0.021² M²)
As both the denominator and numerator have the same unit M², the units are cancelled off.
Equilibrium constant, Kc = [CH₄] [CCl₄] / [CH₂Cl₂]
====
At equilibrium:
[CH₄] = [CCl₄] = 0.2 M
[CH₂Cl₂] = 0.021 M
Kc = [CH₄] [CCl₄] / [CH₂Cl₂] = (0.2 M)² / (0.021 M)² = 91
====
Kc does not have unit.
Kc = (0.2 M)² / (0.021 M)² = (0.2² M²) / (0.021² M²)
As both the denominator and numerator have the same unit M², the units are cancelled off.
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