where is f(x)=4x^2-9/2x^2-x-3 discontinuous?
回答 (3)
2017-08-16 6:53 pm
f(x) = (4x² - 9) / (2x² - x - 3)
f(x) is undefined when denominator is 0, i.e.
2x² - x - 3 = 0
(2x - 3)(x + 1) = 0
Hence, f(x) is discontinuous when x = 3/2 and x = -1
f(x) is undefined when denominator is 0, i.e.
2x² - x - 3 = 0
(2x - 3)(x + 1) = 0
Hence, f(x) is discontinuous when x = 3/2 and x = -1
2017-08-17 12:24 am
f(x) is continuous. All polynomials are continuous.
2017-08-16 8:00 pm
f(x) = (4x^2-9)/(2x^2-x-3)
check where the denominator is 0 to find the points of discontinuity
2x^2-x-3 = 0
2x^2+2x-3x-3 =0
2x(x+1)-3(x+1)=0
(x+1)(2x-3)=0
x=-1 and x=3/2 are points of discontinuity
check where the denominator is 0 to find the points of discontinuity
2x^2-x-3 = 0
2x^2+2x-3x-3 =0
2x(x+1)-3(x+1)=0
(x+1)(2x-3)=0
x=-1 and x=3/2 are points of discontinuity
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