更新1:
Factor by grouping 1.) 12a^3 - 9a + 4a -3 2.) 3n^3 - 4n^2 + 9n-12?
1.) 12a^3 - 9a + 4a -3 2.) 3n^3 - 4n^2 + 9n-12?
回答 (1)
2017-08-16 11:06 am
In 1.) -9a should be -9a² instead
1)
12a³ - 9a² + 4a - 3
= (12a³ - 9a²) + (4a - 3)
= 3a²(4a - 3) + (4a - 3)
= (4a - 3)(3a² + 1)
2)
3n³ - 4n² + 9n - 12
= (3n³ - 4n²) + (9n - 12)
= n²(3n - 4) + 3(3n - 4)
= (3n - 4)(n² + 3)
1)
12a³ - 9a² + 4a - 3
= (12a³ - 9a²) + (4a - 3)
= 3a²(4a - 3) + (4a - 3)
= (4a - 3)(3a² + 1)
2)
3n³ - 4n² + 9n - 12
= (3n³ - 4n²) + (9n - 12)
= n²(3n - 4) + 3(3n - 4)
= (3n - 4)(n² + 3)
收錄日期: 2021-04-18 17:40:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170816023439AAXMeVs