The element nickel (Ni) has a density of 8.91 g/cm3. How many moles of nickel are there in 5.0 L of nickel. (molar mass 58.69 g/mol)?
回答 (3)
2017-08-16 12:38 am
Volume nickel = 5.0 L = 5000 cm³
Mass of nickel = Volume × Density = (5000 cm³) × (8.91 g/cm³) = 44550 g
No. of moles of nickel = Mass / Molar mass = (44550 g) / (58.69 g/mol) = 759.1 mol
Mass of nickel = Volume × Density = (5000 cm³) × (8.91 g/cm³) = 44550 g
No. of moles of nickel = Mass / Molar mass = (44550 g) / (58.69 g/mol) = 759.1 mol
2017-08-16 12:37 am
d = m/V
8.91 g/cm3 = m/V = m/5000
m = 44550 g
so
M = m/n
n = m/M = 44550/58.7 mol =758.9 moles
8.91 g/cm3 = m/V = m/5000
m = 44550 g
so
M = m/n
n = m/M = 44550/58.7 mol =758.9 moles
2017-08-16 12:32 am
1 L = 1 dm3 = 1000 cm3
Hope that helps
Hope that helps
收錄日期: 2021-04-18 17:38:59
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