For the following reaction:
2NH3 (g) N2 (g) + 3H2 (g)
The equilibrium concentrations are: [NH3] = 0.22 M, [N2] = 0.54 M, and [H2] = 0.66 M. What is the value of the equilibrium constant for this reaction?
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2017-08-11 9:21 pm
回答 (2)
2017-08-11 9:39 pm
2NH₃(g) ⇌ N₂(g) + 3H₂(g) …. Kc
Equilibrium constant, Kc = [N₂] [H₂]³ / [NH₃]² = 0.54 × 0.66³ / 0.22² = 3.2
Equilibrium constant, Kc = [N₂] [H₂]³ / [NH₃]² = 0.54 × 0.66³ / 0.22² = 3.2
2017-08-11 9:23 pm
Idk
收錄日期: 2021-04-18 17:39:21
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