1.a>b,a+b=7,a*b=3,a-b?
2.(9+1)*(9^2+1)*(9^4+1)=9^8-1/k,k=?
3.a+b=5,a*b=3,(a-b)^2 ?
4.99*101-(100-1)^2=?
5.(1-1/2^2)*(1*1/3^2)..*(1-1/10^2)=?
回答 (1)
1.a>b,a+b=7,a*b=3,a-b?
Sol
p=a-b>0
p^2=(a-b)^2=(a+b)^2-4ab=49-12=37
p=√37
2.(9+1)*(9^2+1)*(9^4+1)=(9^8-1)/k,k=?
Sol
A=(9+1)*(9^2+1)*(9^4+1)
8A=(9-1)*(9+1)*(9^2+1)*(9^4+1)
=(9^2-1)*(9^2+1)*(9^4+1)
=(9^4-1)*(9^4+1)
=9^8-1
A=(9^8-1)/8
k=8
3.a+b=5,a*b=3,(a-b)^2 ?
Sol
(a-b)^2=(a+b)^2-4ab
=5^2-12
=13
4.99*101-(100-1)^2=?
Sol
99*101-(100-1)^2
=99*101-99^2
=99*(101-99)
=198
5.(1-1/2^2)*(1*1/3^2)..*(1-1/10^2)=?
Sol
A=(1-1/2)*(1-1/3)*(1-1/4)*…*(1-1/10)
=(1/2)*(2/3)*(3/4)*…*(8/9)*(9/10)
=1/10
B=(1+1/2)*(1+1/3)*(1+1/4)*…*(1+1/10)
=(3/2)*(4/3)*(5/4)*…*(10/9)*(11/10)
=11/2
(1-1/2^2)*(1*1/3^2)..*(1-1/10^2)
=AB
=11/10
收錄日期: 2021-04-30 22:24:33
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