Ajay completed 2/7th of a piece of work in 14 days. How many days will he take to complete the remaining work.?

Method 1 :

Let d be the number of days taken to complete the remaining work.

(14 days) : (d days) = (2/7) : [1 - (2/7)]
14 : d = (2/7) : (5/7)
14 : d = 2 : 5
2d = 70
d = 35

Hence, number of days taken for the remaining work = 35 days

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Method 2 :

Number of days taken for the whole work
= 14 ÷ (2/7) days
= 14 × (7/2) days
= 49 days

Number of days taken for the remaining work
= (49 - 14) days
= 35 days

1/7 of the work takes 7 days
7/7 of the work takes 49 days
Answer 35 more days

2/7______________14 days
1/7_______________7 days
5/7______________35 days to complete

(2/7)x = 14
x = 14 * (7/2)
x = 49 --> Total days

Remaining days = 49 - 14 = 35 days

Ajay completed 2/7th of a piece of work in 14 days.
He will take 35 days to complete the remaining work.

A did (2/7)w in 14d. So he can do (1/7)w in 7d. To complete w, A must do (5/7)w. This will
take him 5*7d = 35d.

35 to complete the remainder but 49 total

2/7 of work in 14 days.

Therefore he would complete 1/7 of work in 7 days.

7 x 7 = 49 days.

49 days.

49 days.