What is the molarity of a solution made by mixing 2.80g of KOH with enough water to make 750. ml of solution?
回答 (2)
2017-07-31 2:14 pm
Molar mass of KOH = (39.0 + 16.0 + 1) g/mol = 56.0 g/mol
No. of moles of KOH = (2.80 g) / (56.0 g/mol) = 0.0500 mol
Volume of the solution = (750 mL) / (1000 mL/L) = 0.750 L
Molarity of the solution = (0.0500 mol) / (0.750 mL) = 0.0673 M
No. of moles of KOH = (2.80 g) / (56.0 g/mol) = 0.0500 mol
Volume of the solution = (750 mL) / (1000 mL/L) = 0.750 L
Molarity of the solution = (0.0500 mol) / (0.750 mL) = 0.0673 M
2017-08-01 12:11 am
mol(KOH) = 2.80/ (39+16+1)
mol(KOH) = 28. /56 = 0.05
Hence
0.05 = [conc] X 750 mL / 1000 mL
[conc] = 0.05 x 1000 / 750
[conc] = 0.0666 mol dm^-3
mol(KOH) = 28. /56 = 0.05
Hence
0.05 = [conc] X 750 mL / 1000 mL
[conc] = 0.05 x 1000 / 750
[conc] = 0.0666 mol dm^-3
收錄日期: 2021-04-24 00:37:19
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https://hk.answers.yahoo.com/question/index?qid=20170731053328AAtZTp9