Intro to Chem?
2017-07-26 11:53 pm
The decomposition of baking soda produces carbon dioxide gas. If 42.6 mL of wet gas is collected over water at 22 C and 764 mm Hg, what is the volume of dry gas at STP conditions? Vapor pressure of H2O at 22C is 19.8 mm Hg.
回答 (1)
2017-07-27 12:12 am
CO₂ gas collected: P₁ = (764 - 19.8) mmHg, V₁ = 42.6 mL , T₁ = (273 + 22) K
Dry CO₂ at STP: P₂ = 760 mmHg, V₂ = ? mL, T₂ = 273 K
For a fixed amount of gas: P₁V₁/T₁ = P₂V₂/T₂
Then, V₂ = V₁ × (P₁/P₂) × (T₂/T₁)
Volume of dry CO₂ at STP, V₂ = (42.6 mL) × [(764 - 19.8) / 760] × [273 / (273 + 22)] = 38.6 mL
Dry CO₂ at STP: P₂ = 760 mmHg, V₂ = ? mL, T₂ = 273 K
For a fixed amount of gas: P₁V₁/T₁ = P₂V₂/T₂
Then, V₂ = V₁ × (P₁/P₂) × (T₂/T₁)
Volume of dry CO₂ at STP, V₂ = (42.6 mL) × [(764 - 19.8) / 760] × [273 / (273 + 22)] = 38.6 mL
收錄日期: 2021-04-18 17:25:15
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