請問數學高手,糖果有a顆,甲先取一半少一顆,乙再取剩下的2/3少一顆,則乙共取?顆?
回答 (3)
2017-07-25 9:07 pm
✔ 最佳答案
甲先取一半少 1 顆, 甲取了糖 : (a/2)-1剩下的糖 = a - [ (a/2)-1 ] =(a/2)+1
乙再取剩下的2/3少 1 顆, 乙共取 :
= (2/3) [ (a/2)+1 ] -1
= [(a/3)+2/3] -1
= (a/3) -(1/3)
= (a-1) /3 顆
2017-07-31 8:38 am
2/3[a-(a/2-1)]-1=2/3(a/2+1)-1=a/3-1/3
2017-07-26 11:41 am
(a +1)/3 顆
收錄日期: 2021-04-24 00:34:55
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170725124422AAIPXz8