URGENT !! Plz solve below question based on the concept of displacement in nth second in physics.?

[匿名]

2017-07-19 4:54 pm

a body moving in a straight line with constant acceleration 10m/s2 covers a distance of 40m in the 4th sec.how much distance will it cover in the 6 th sec ?

回答 (1)

wanszeto

2017-07-19 5:29 pm

✔ 最佳答案

Let u m/s be the initial speed (t = 0).

s = ut + (1/2) at²

Distance for 3 seconds = u(3) + (1/2)(10)(3)² = (3u + 45) m
Distance for 4 seconds = u(4) + (1/2)(10)(4)² = (4u + 80) m

(Distance for 4 seconds) - (Distance for 3 seconds) = Distance in the 4th second
(4u + 80) - (3u + 45) = 40
u + 35 = 40
Initial speed, u = 5 m/s

Distance for 5 seconds = (5)(5) + (1/2)(10)(5)² = 150 m
Distance for 6 seconds = (5)(6) + (1/2)(10)(6)² = 210 m

Distance in the 6th second = (Distance for 6 seconds) - (Distance for 5 seconds)
= (210 - 150) m
= 60 m

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