What volume of gas would result if 280. mL of neon gas is compressed from 1.67 atm to 2.14 atm at constant temperature?

Initial: P₁ = 1.67 atm, V₁ = 280 mL
Final: P₂ = 2.14 atm, V₂ = ? mL

For a fixed amount of gas under constant temperature: P₁V₁ = P₂V₂
Then, V₂ = V₁ × (P₁/P₂)

Final volume, V₂ = (280 mL) × (1.67/2.14) = 219 mL