Help me find f if f′′′(x)=sin(x),f(0)=−10,f′(0)=−6,f′′(0)=−3, I've attempted it but don't know what's wrong?

f'''(x) = sin(x)
∫f'''(x) = f''(x) = -cos(x) + C
∫f''(x) = f'(x) = -sin(x) + Cx + D
∫f'(x) = f(x) = cos(x) + ½Cx² + Dx + E

f''(0) = -cos(0) + C
-3 = -1 + C
C = -2

f'(0) = -sin(0) + (-2)(0) + D
-6 = D

f(0) = cos(0) + ½(-2)(0)² + (-6)(0) + E
-10 = 1 + E
E = -11

f(x) = cos(x) + ½(-2)x² + (-6)x + (-11)
f(x) = cos(x) - x² - 6x - 11