Consider the function, y=2*root2+4cos(2x-pi/2)?
2017-07-14 12:23 pm
How do you find all the x-intercepts of the function on the interval [0,pi)?
回答 (1)
2017-07-14 3:40 pm
✔ 最佳答案
0 ≦ x < π0 ≦ 2x < 2π
- π/2 ≦ 2x - π/2 < (3/2)π
y = 2√2 + 4*cos ( 2x - π/2 ) = 0
cos ( 2x - π/2 ) = - 2√2 / 4 = - 1/√2
2x - π/2 = (3/4)π , (5/4)π
2x = (5/4)π , (7/4)π
x = (5/8)π , (7/8)π ..... Ans
收錄日期: 2021-05-02 14:12:45
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https://hk.answers.yahoo.com/question/index?qid=20170714042330AAB4C1G