If 5x + 6 = 41, then x + 3 is?

5(7) + 6 = 41

Plug in 7 to 'x + 3'

7 + 3 = 10

10

5x+6 = 41
x = 7
7 + 3 = ?

First, you need to solve for 'x'. You need to isolate the x on one side of the equation,
so start by eliminating the 6. You do this by subtracting 6 from both sides of the equation.
5x + 6 ( - 6 ) = 41 - 6
5x + 0 = 35
To further make the 'x' alone, divide by 5 on both sides of equation:
5x/5 = 35/5
x = 35/5
x = 7
Now wherever you see an 'x', you can write 7 instead.
So for x + 3, it's now 7 + 3
And this equals 10.

5x + 6 = 41
5x = 35
x = 7
x + 3 = 7 + 3 = 10

5x + 6 = 41; 5x =41 - 6 i.e., 35; x = 7.
x + 3 = 7 + 3 i.e., 10.

10.

5x + 6 = 41

5x = 41 - 6

5x = 35

x = 35/5

x = 7

Now that we know the value of x, plug 7
into x + 3.

So, x + 3 becomes 7 + 3 or 10.

5x = 35
x = 7

x + 3 = 10

5(x +3) = 5x +15
.. = (5x +6) +9
.. = 41 +9
.. = 50
x +3 = 50/5
x +3 = 10

5x + 6 = 41
x + 3 = 10

5x = 41 - 6
5x = 35
x = 35/5
x = 7

x + 3 = 7 + 3 = 10

5x + 6 = 41
5x = 41 - 6
5x = 35
x = 35/5
x = 7
x + 3 = 7 + 3
x + 3 = 10

5x + 6 = 41
x = (41 - 6) / 5
x = 35 / 5
x = 7

x + 3
= 7 + 3
= 10