Surds and indices question?
回答 (1)
2017-06-13 3:42 pm
✔ 最佳答案
1/( 1 + a + b⁻¹ ) + 1/( 1 + b + c⁻¹ ) + 1/( 1 + c + a⁻¹ )= b/( b + ab + 1 ) + 1/( 1 + b + ab ) + 1/( 1 + a⁻¹b⁻¹ + a⁻¹ )
= ( b + 1 )/( b + ab + 1 ) + ab/( ab + 1 + b )
= ( b + 1 + ab )/( b + ab + 1 )
= 1 ..... Ans
收錄日期: 2021-05-02 14:12:03
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