試求介於y=x*3 與 y=x*2 圖形之間的面積?
回答 (3)
2017-06-10 3:30 pm
Sol
x^2=x^3
x^2－x^3=0
x^2(x－1)=0
x=0(重根) or x=1
面積=∫(0 to 1)_x^2－x^3dx
=x^3/3－x^4/4｜(0 to 1)
=1/3－1/4
=1/12
x^2=x^3
x^2－x^3=0
x^2(x－1)=0
x=0(重根) or x=1
面積=∫(0 to 1)_x^2－x^3dx
=x^3/3－x^4/4｜(0 to 1)
=1/3－1/4
=1/12
2017-06-11 8:46 am
y=x^3
y=x^2
(x^3)-(x^2)=0
x^2(x-1)=0
x=0 or x=1
面積
=∫(0 to 1) [(x^3)-(x^2)]dx
=|0.25x^4 -(1/3)x^3| | (0 to 1)
=|0.25-(1/3)|
=1/12
y=x^2
(x^3)-(x^2)=0
x^2(x-1)=0
x=0 or x=1
面積
=∫(0 to 1) [(x^3)-(x^2)]dx
=|0.25x^4 -(1/3)x^3| | (0 to 1)
=|0.25-(1/3)|
=1/12
2017-06-10 1:28 pm
這麼弱智的問題你當初怎麼沒有好好聽你的老師講課
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