How do I tackle this problem?

2017-06-08 8:07 am
Find the equation of the line that contains the point
P(−4, −1)
and is perpendicular to the graph of
y = −
4
5
x − 1.

回答 (2)

2017-06-08 9:13 am
Your wonderful typography does not communicate the value of the slope of your line. If that slope is "m", then the equation of the perpendicular line through the point can be written using point-slope form as
.. y = (-1/m)(x +4) -1
You can simplify or choose a different form as you may desire.

If your line is
.. y = 4/5x -1
the line you want is
.. y = -5/4(x +4) -1
.. y = (-5/4)x -6 . . . . simplified to slope-intercept form
.. 5x +4y = -24 . . . rearranged to standard form


If your line is
.. y = -4/5x -1
the line you want is
.. y = 5/4(x +4) -1
.. y = (5/4)x +4 . . . . simplified to slope-intercept form
.. 5x -4y = -16 . . . .rearranged to standard form
2017-06-08 8:54 am
what's " graph of
y = −
4
5
x − 1" ?


收錄日期: 2021-05-01 14:58:46
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20170608000714AAKq3aa

檢視 Wayback Machine 備份