How many moles of hydrogen are in a 3.32 L tank when the pressure is 215.6kPa and the temperature is 48.8?

Case I : The temperature is "48.8°C".

P = 215.6 kPa
V = 3.32 L
n = ? mole
R = 8.314 J / (mol K)
T = (273.2 + 48.8) K = 322.0 K

Gas law: PV = nRT
Then, n = PV/(RT)

Number of moles of H₂ = 215.6 × 3.32 / (8.314 × 322.0) mol = 0.267 mol


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Case I : The temperature is "48.8 K".

P = 215.6 kPa
V = 3.32 L
n = ? mole
R = 8.314 J / (mol K)
T = 48.8 K

Gas law: PV = nRT
Then, n = PV/(RT)

Number of moles of H₂ = 215.6 × 3.32 / (8.314 × 48.8) mol = 1.76 mol