Chemistry help?
2017-05-31 1:05 am
A solution was prepared by 14.8g of soduim hydroxide in 600mL of water in flask #1. At this point, 127mL of the solution was diluted to 1.5L in flask#2. What is the concentration of the solution in flask #2?
回答 (1)
2017-05-31 1:11 am
Calculate the molarity of the initial solution:
14.8 g NaOH / 40.0 g/mol = 0.370 mol NaOH / 0.600 L = 0.617 M NaOH
Now, use M1V1 = M2V2 to calculate the final concentration:
0.617 M (127 mL) = M2 (1500 mL)
M2 = 0.052 M NaOH
14.8 g NaOH / 40.0 g/mol = 0.370 mol NaOH / 0.600 L = 0.617 M NaOH
Now, use M1V1 = M2V2 to calculate the final concentration:
0.617 M (127 mL) = M2 (1500 mL)
M2 = 0.052 M NaOH
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