✔ 最佳答案
How many grams of KCl would you need to weight out to prepare 0.25 L of 2.00 M KCl solution?
Number of moles of KCl needed = (2.00 mol/L) × (0.25 L) = 0.5 mol
Molar mass of KCl = (39.0 + 35.5) g/mol = 74.5 g/mol
Mass of KCl needed = (0.5 mol) × (74.5 g/mol) = 37.3 g