Solve the differential equation (dy/dx) e^x - (dy/dx) = y e^x , given x and y are greater/ equal to 2, and y(3)=2 .?
回答 (1)
2017-05-30 5:21 am
✔ 最佳答案
(dy/dx)( e^x - 1) = y e^xdy/y = e^x/(e^x-1)
integrate both sides
ln(y) = ln[C(e^x - 1)]
y = C(e^x - 1)
y(3)=2 --->C=2/(e^3-1)
hence
y = 2(e^x -1)/(e^3 -1
收錄日期: 2021-04-24 00:28:48
原文連結 [永久失效]:
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